Entropy Calculator
How it Works
01Pick a Mode
Reaction ΔS, Gibbs free energy, or isothermal ideal-gas expansion / compression.
02Reaction ΔS
ΔS_rxn = ΣS_products − ΣS_reactants. Use standard molar entropies from tables.
03Gibbs ΔG = ΔH − TΔS
Negative ΔG = spontaneous. Temperature is the deciding lever.
04Ideal-Gas ΔS
ΔS = nR·ln(V₂/V₁) (volume change) or −nR·ln(P₂/P₁) (pressure change) at constant T.
What is an Entropy Calculator?
Each mode lives in its own collapsible section with method-specific inputs and unit selectors. Reaction ΔS takes total entropies of products and reactants in J / (mol · K) (default) or alternatives (kJ / mol · K, cal / mol · K). Gibbs ΔG takes ΔH in J / kJ / cal / kcal, T in °C / K / °F, and ΔS in J/K — the calculator auto-converts to SI internally and computes ΔG with spontaneity classification. Ideal-gas ΔS takes amount in moles, then either two volumes (m³ / L / mL) OR two pressures (Pa / kPa / atm / bar) depending on which state variable changed; the result depends on the ratio V₂/V₁ (or P₂/P₁), not the absolute values.
Designed for physical chemistry students learning thermodynamics, undergraduate and graduate chemistry coursework, chemical engineers analyzing reactor and separation processes, biochemists characterizing enzyme energetics, and atmospheric scientists modeling adiabatic / isothermal gas processes, the tool runs entirely in your browser — no account, no data stored.
Pro Tip: Pair this with our Partial Pressure Calculator for ideal-gas mixtures, our Rate Constant Calculator for kinetics, or our Molarity Calculator for stock preparation.
How to Use the Entropy Calculator?
How are entropy quantities calculated?
Three standard entropy equations from undergraduate physical chemistry. Each applies to a specific physical situation; together they cover the most-used entropy calculations in chemistry, biochemistry, and chemical engineering.
References: Atkins' Physical Chemistry (12th ed.); CRC Handbook of Chemistry and Physics; IUPAC Compendium of Chemical Terminology.
1. Reaction Entropy Change
ΔS_rxn = Σ ν_i · S°(product i) − Σ ν_j · S°(reactant j)
where ν are stoichiometric coefficients and S° are standard molar entropies in J · mol⁻¹ · K⁻¹ at 298.15 K and 1 bar. Standard entropies are tabulated in the CRC Handbook (Section 5) and NIST WebBook; common examples: O₂(g) 205.1; H₂(g) 130.7; H₂O(l) 69.9; H₂O(g) 188.8; CO₂(g) 213.7; NaCl(s) 72.1; diamond 2.4; graphite 5.7. Higher S° = more disordered species (gases > liquids > solids; complex molecules > simple atoms).
2. Gibbs Free Energy
ΔG = ΔH − T · ΔS
where ΔH is the enthalpy change (J), T is absolute temperature (K), and ΔS is the entropy change (J/K). Sign of ΔG determines spontaneity: ΔG < 0 spontaneous; ΔG > 0 non-spontaneous (reverse is spontaneous); ΔG = 0 equilibrium. The four sign-combination cases: ΔH < 0, ΔS > 0 always spontaneous; ΔH > 0, ΔS < 0 never spontaneous; ΔH < 0, ΔS < 0 spontaneous below T = ΔH/ΔS (enthalpy-driven, low-T); ΔH > 0, ΔS > 0 spontaneous above T = ΔH/ΔS (entropy-driven, high-T).
3. Isothermal Entropy Change of an Ideal Gas
ΔS = n · R · ln(V₂ / V₁) (volume change at constant T)
ΔS = −n · R · ln(P₂ / P₁) (pressure change at constant T; equivalent via Boyle's law PV = const)
where n is moles, R = 8.31446 J/(mol·K) is the universal gas constant. Result is in J/K (total entropy change of the system, NOT per mole). The negative sign for the pressure form reflects that increasing pressure decreases entropy (gas confined to smaller effective volume).
Worked Example — Reaction Entropy: 2 H₂(g) + O₂(g) → 2 H₂O(l)
- Σ S°(products) = 2 × 69.9 (H₂O liquid) = 139.8 J/(mol·K).
- Σ S°(reactants) = 2 × 130.7 (H₂) + 1 × 205.1 (O₂) = 466.5 J/(mol·K).
- ΔS_rxn = 139.8 − 466.5 = −326.7 J/(mol·K).
- Negative ΔS — gas → liquid converts highly disordered phase to ordered phase; entropy decreases substantially. Yet the reaction is highly spontaneous (combustion!) because ΔH is very negative (−571.6 kJ/mol) and overwhelms TΔS at room T.
Worked Example — Gibbs Free Energy
Same reaction at 298 K: ΔH = −571,600 J; ΔS = −326.7 J/K (using calculation above × 1 mol of reaction extent).
- ΔG = ΔH − T·ΔS = −571,600 − (298 × (−326.7)) = −571,600 + 97,357 = −474,243 J = −474.2 kJ.
- Strongly negative ΔG → strongly spontaneous (matches our intuition that hydrogen + oxygen → water releases enormous energy).
- The unfavorable entropy term (T·ΔS = +97.4 kJ added back to free energy) is overwhelmed by the favorable enthalpy term (ΔH = −571.6 kJ).
Worked Example — Isothermal Ideal Gas
1 mol of ideal gas isothermally expanded from 1 L to 10 L at constant T:
- ΔS = n·R·ln(V₂/V₁) = 1 × 8.314 × ln(10) = 8.314 × 2.303 = +19.14 J/K.
- Positive ΔS — gas expanding to larger volume increases positional entropy. Standard 10× expansion gives standard entropy increase of 19.14 J/K (independent of T as long as T stays constant; independent of which gas as long as it's ideal).
- Equivalent pressure interpretation: starting at 1 atm, expanding to 10× volume drops pressure to 0.1 atm. ΔS = −n·R·ln(0.1/1) = −8.314 × (−2.303) = +19.14 J/K. ✓ Same answer.
Entropy – Worked Examples
- Σ S°_products = 2(69.9) = 139.8 J/(mol·K).
- Σ S°_reactants = 2(130.7) + 1(205.1) = 466.5 J/(mol·K).
- ΔS_rxn = 139.8 − 466.5 = −326.7 J/(mol·K).
- Negative because 3 mol gas → 2 mol liquid (large drop in molecular freedom).
Example 2 — Gibbs ΔG at 298 K for the same reaction. ΔH = −571,600 J, T = 298 K (= 25 °C), ΔS = −326.7 J/K.
- ΔG = ΔH − T·ΔS = −571,600 − (298)(−326.7) = −571,600 + 97,357 = −474,243 J = −474 kJ.
- Strongly negative → SPONTANEOUS at 25 °C. Good, since H₂ + O₂ → H₂O is the basic combustion reaction.
- Note: the favorable enthalpy completely dominates; entropy fights back but loses by 5× margin.
Example 3 — Ideal Gas Volume Expansion (10×). 1 mol gas, V₁ = 1 L, V₂ = 10 L, isothermal.
- ΔS = n·R·ln(V₂/V₁) = 1 × 8.314 × ln(10) = +19.14 J/K.
- Positive — molecules have more positions available (larger volume).
- The result is independent of T (as long as constant) and independent of which gas (as long as ideal). Universal entropy of 10× expansion = 19.14 J/K per mol.
Example 4 — Ideal Gas Pressure Compression. 0.5 mol N₂, P₁ = 1 atm, P₂ = 5 atm, isothermal at 298 K.
- ΔS = −n·R·ln(P₂/P₁) = −(0.5)(8.314)(ln 5) = −0.5 × 8.314 × 1.609 = −6.69 J/K.
- Negative — gas compressed to higher pressure (smaller effective volume) → fewer molecular positions → lower entropy.
- This is the entropy LOSS during compression; the surroundings gain entropy from heat dissipation, so universe entropy still increases (second law satisfied).
Example 5 — Spontaneity Reversal with Temperature. Endothermic reaction with positive entropy: ΔH = +50 kJ, ΔS = +100 J/K. Find the temperature where ΔG = 0.
- ΔG = 0 when ΔH = T·ΔS → T = ΔH / ΔS = 50,000 / 100 = 500 K = 227 °C.
- At T < 500 K: ΔG > 0 (non-spontaneous; enthalpy wins).
- At T > 500 K: ΔG < 0 (spontaneous; entropy wins as T·ΔS grows).
- Classic example of an entropy-driven reaction — spontaneity "turns on" above the crossover temperature. Ammonium nitrate decomposition (NH₄NO₃ → N₂O + 2 H₂O) follows this pattern; spontaneous only above ~150 °C.
Who Should Use the Entropy Calculator?
Technical Reference
Statistical-Mechanical Definition (Boltzmann). Entropy is fundamentally S = k_B · ln Ω, where k_B = 1.381 × 10⁻²³ J/K is the Boltzmann constant and Ω is the number of microstates accessible to the system at the given macroscopic state. This Boltzmann formula (engraved on Boltzmann's tombstone in Vienna) is the molecular-level definition; the macroscopic thermodynamic entropy is the same quantity scaled to per-mole units via R = N_A · k_B. Higher Ω (more accessible microstates) = higher entropy. Heat dispersal, gas expansion, mixing of components, phase transitions to less ordered states — all increase Ω and thus S.
Standard Molar Entropies (CRC Handbook, 298.15 K, 1 bar):
- Gases: H₂ 130.7, He 126.2, N₂ 191.6, O₂ 205.1, Ar 154.8, CO 197.7, CO₂ 213.7, H₂O(g) 188.8, NH₃ 192.5, CH₄ 186.3, C₂H₄ 219.6, C₂H₆ 229.6.
- Liquids: H₂O 69.9, ethanol 159.9, methanol 126.8, benzene 173.4, acetone 200.4, mercury 76.0.
- Ionic solids: NaCl 72.1, KCl 82.6, CaCO₃ 92.9, NaOH 64.5, KOH 78.9, CuSO₄ 109.0.
- Elements (solids): C(diamond) 2.4, C(graphite) 5.7, Al 28.3, Fe 27.3, Cu 33.2, Zn 41.6, Pb 64.8, Ag 42.6, Au 47.4.
- Aqueous ions (relative to H⁺ = 0): Na⁺ 59.0, K⁺ 102.5, Ca²⁺ −53.1, Cl⁻ 56.5, OH⁻ −10.8, NO₃⁻ 146.4. (Note: ionic entropies are RELATIVE; conventionally H⁺(aq) = 0.)
Trends in Standard Entropy:
- Gases > liquids > solids: dramatically. Translational entropy of gas molecules (3 degrees of freedom × ~50 J/(mol·K) each) dominates; liquid molecules are constrained to ~50% of gas-phase entropy; solid molecules constrained to a few percent.
- More atoms / heavier molecules → higher S°: more vibrational modes available. Compare CH₄ 186 vs C₂H₆ 230 J/(mol·K).
- Increasing temperature → higher S°: S(T) = S(298) + ∫(Cp/T)dT. Heating from 298 K to 500 K typically adds 10-30 J/(mol·K) for most substances.
- Phase transitions: melting adds ΔS_fusion = ΔH_fusion / T_melt; vaporization adds ΔS_vap = ΔH_vap / T_boil. Trouton's rule: ΔS_vap ≈ 88 J/(mol·K) for many liquids at their normal boiling point — a remarkable empirical regularity.
- Polymorphism: different crystal forms of the same compound have different S°. Diamond (highly ordered tetrahedral lattice) S° = 2.4; graphite (layered structure with weaker bonds) S° = 5.7 — graphite has 2.4× more disorder per mole of carbon.
Gibbs vs Helmholtz Free Energy. The Gibbs equation ΔG = ΔH − T·ΔS applies to processes at constant temperature AND constant pressure (the typical lab / atmospheric / biological condition). For processes at constant T and constant volume (some industrial reactors, sealed-volume scenarios), use the Helmholtz free energy: ΔA = ΔU − T·ΔS, where ΔU is the internal energy change. For constant-V processes ΔA replaces ΔG as the spontaneity criterion. Most chemistry happens at constant pressure (atmospheric, vessel open or with vapor space), so Gibbs is the more commonly-taught form.
The Four Spontaneity Cases:
- Case 1: ΔH < 0, ΔS > 0 → ΔG < 0 ALWAYS. Always spontaneous, all temperatures. Examples: combustion (most), oxidation reactions producing gases, decomposition of unstable compounds. The "easy" case.
- Case 2: ΔH > 0, ΔS < 0 → ΔG > 0 ALWAYS. Never spontaneous. Examples: synthesis of unstable compounds from stable ones (e.g. forming ozone O₃ from O₂ alone — requires energy input). The reverse is always spontaneous.
- Case 3: ΔH < 0, ΔS < 0 → ENTHALPY-DRIVEN. Spontaneous below crossover T = ΔH/ΔS; non-spontaneous above. Examples: gas-to-liquid condensation, freezing, polymerization (loss of monomer translational entropy). Cools to spontaneous; heats to non-spontaneous.
- Case 4: ΔH > 0, ΔS > 0 → ENTROPY-DRIVEN. Spontaneous above crossover T = ΔH/ΔS; non-spontaneous below. Examples: NH₄NO₃ decomposition (cool packs), evaporation, melting of ice, dissolution of NaCl in water (slightly endothermic but entropy-driven; salt forms entropic ions). Heats to spontaneous.
Reaction Quotient and Equilibrium Constant. The Gibbs equation generalizes for non-standard concentrations: ΔG = ΔG° + RT · ln Q, where Q is the reaction quotient (ratio of product to reactant activities, raised to stoichiometric coefficients). At equilibrium, ΔG = 0 and Q = K (equilibrium constant), so ΔG° = −RT · ln K. This is the bridge from thermodynamics to chemical equilibrium — knowing ΔG° (from tabulated ΔH° and S° data) lets you predict K, which determines the equilibrium concentrations of products and reactants.
Isothermal vs Adiabatic Processes. The ΔS = nR·ln(V₂/V₁) formula assumes isothermal (constant T). For adiabatic reversible expansion (no heat exchange with surroundings), T DECREASES as V increases, and ΔS = 0 (reversible adiabatic = isentropic). For adiabatic irreversible expansion (free expansion into vacuum), ΔS > 0 because the process is irreversible (Joule expansion). The ideal-gas isothermal formula is the simplest case; real processes interpolate between isothermal and adiabatic depending on heat transfer rate vs expansion rate.
Reversible vs Irreversible. The formula ΔS = nR·ln(V₂/V₁) gives the entropy change OF THE SYSTEM, which is path-independent (S is a state function). For a reversible isothermal expansion (infinitely slow, in contact with a heat bath at T): ΔS_surroundings = −nR·ln(V₂/V₁); ΔS_universe = 0. For an irreversible isothermal expansion (e.g. against a constant external pressure): ΔS_system is the same value (state function!), but ΔS_surroundings < nR·ln(V₂/V₁), so ΔS_universe > 0. The system's entropy doesn't care about path; the universe's entropy reveals whether the process is reversible (ΔS_univ = 0) or not (ΔS_univ > 0).
Real Gas Departure from Ideal Behaviour. The ΔS = nR·ln(V₂/V₁) formula assumes ideal gas (no intermolecular forces, no molecular volume). For real gases, especially at high pressures (> 10 atm) or near critical points, use a real-gas equation of state with proper entropy departure functions: ΔS_real = ΔS_ideal + (S − S^ideal)_dep,2 − (S − S^ideal)_dep,1. The Van der Waals, Peng-Robinson, or Soave-Redlich-Kwong equations give departure functions in closed form. For typical lab and atmospheric conditions (1 atm, 0-100 °C), ideal gas error is < 1% for most gases (less than the precision of typical thermodynamic data).
Key Takeaways
Frequently Asked Questions
What is the Entropy Calculator?
Pro Tip: Pair this with our Partial Pressure Calculator for ideal-gas mixtures.
What's the formula for entropy change?
What does positive vs negative ΔS mean?
How does ΔG predict reaction spontaneity?
What are the four spontaneity cases?
Why does volume expansion increase entropy?
What's the universal gas constant R?
What's the difference between system, surroundings, and universe entropy?
When does the ideal gas approximation break down?
How do I find standard molar entropies S°?
What's the second law of thermodynamics?
Disclaimer
Standard molar entropies tabulated at 298.15 K and 1 bar; for other conditions use the temperature integration ΔS(T) = ΔS(298) + ∫(Cp/T)dT. Reaction-ΔS mode assumes user has multiplied each species' S° by its stoichiometric coefficient before summing. Ideal-gas formulas assume ideal behaviour (degrades at high pressure, low temperature, polar molecules); for non-ideal use a real-gas equation of state with entropy departure functions. The Gibbs equation applies at constant T and constant P; for constant-V processes use the Helmholtz equation ΔA = ΔU − TΔS. References: Atkins' Physical Chemistry, CRC Handbook of Chemistry and Physics, NIST WebBook, JANAF Thermochemical Tables.